## Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 8 - Polynomials and Factoring - 8-5 Factoring x2+bx+c - Practice and Problem-Solving Exercises - Page 517: 54

(h+15j)(h-6j)

#### Work Step by Step

You are given $h^{2}$+9hj-90$j^{2}$. Factor it out: $h^{2}$+15hj-6hj$j^{2}$ -break out the middle value- ($h^{2}$+15hj)+(-6hj-90$j^{2}$) -group the first two and last two terms- h(h+15j)-6j(h+15j) -Find the GCF of each grouping- (h+15j)(h-6j) -factor out the common term- =(h+15j)(h-6j)

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