## Algebra 1: Common Core (15th Edition)

$(t-4)(t-6)$
$-10$ is negative, so we list negative factors of $24$. $\left[\begin{array}{llll} \text{ Factors of 24 } & \text{Sum of factors}-1 \text{ and }-24 & -25 & \\ -2\text{ and }-12 & -14 & \\ -3\text{ and }-8 & -11 & \\ -4\text{ and }-6 & -10 & \text{...is what we need} \end{array}\right]$ $t^{2}-10t+24=(t-4)(t-6)$