Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-5 Factoring x2+bx+c - Lesson Check - Page 515: 4

Answer

$(a+4b)(a+8b)$

Work Step by Step

$12$ is positive, so we list positive factors of $32$. $\left[\begin{array}{lll} \text{Factors of 32 } & \text{Sum of factors}1 \text{ and }32 & 33\\ 2\text{ and }16 & 18 & \\ 4\text{ and }8 & 12 & \text{...is what we need} \end{array}\right]$ $a^{2}+12ab+32b^{2}=(a+4b)(a+8b)$ Check: $(a+4b)(a+8b)=$ ...use the FOIL method. $=a^{2}+8ab+4ab+32b^{2}$ ...add like terms. $=a^{2}+12ab+32b^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.