Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-5 Factoring x2+bx+c - Got It? - Page 512: 1

Answer

$r^{2}+11r+24=(r+3)(r+8)$

Work Step by Step

$11$ is positive, so we list positive factors of $24$. $\left[\begin{array}{lll} \text{Factors of 24 } & \text{Sum of factors}\\ 1 \text{ and }24 & 25\\ 2\text{ and } 12 & 14 & \\ 3\text{ and }8 & 11 & \text{is what we need}\\ 4\text{ and }6 & 10 & \end{array}\right]$ $r^{2}+11r+24=(r+3)(r+8)$ Check: $(r+3)(r+8)=$ ...use the FOIL method. $=r^{2}+8r+3r+24$ ...add like terms. $=r^{2}+11r+24$
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