## Algebra 1: Common Core (15th Edition)

$9(8x^{3}+6x^{2}+3)$
List the factors of each term, note the common factors: $72x^{3}=2\cdot 2\cdot 2\cdot(3\cdot 3)\cdot x\cdot x\cdot x$ $54x^{2}=2\cdot(3\cdot 3)\cdot 3\cdot x\cdot x\cdot x$ $27=(3\cdot 3)\cdot 3$ GCF=$(3\cdot 3)$, or $9$. $72x^{3}+54x^{2}+27$ = ...factor out the GCF from each term. $=9(8x^{3})+9(6x^{2})+9(3)$ ...apply the Distributive Property. =$9(8x^{3}+6x^{2}+3)$