Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Soecial Cases - Practice and Problem-Solving Exercises - Page 509: 70

Answer

$9(8x^{3}+6x^{2}+3)$

Work Step by Step

List the factors of each term, note the common factors: $72x^{3}=2\cdot 2\cdot 2\cdot(3\cdot 3)\cdot x\cdot x\cdot x$ $54x^{2}=2\cdot(3\cdot 3)\cdot 3\cdot x\cdot x\cdot x$ $27=(3\cdot 3)\cdot 3$ GCF=$(3\cdot 3)$, or $9$. $72x^{3}+54x^{2}+27$ = ...factor out the GCF from each term. $=9(8x^{3})+9(6x^{2})+9(3)$ ...apply the Distributive Property. =$9(8x^{3}+6x^{2}+3)$
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