Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Soecial Cases - Got It? - Page 506: 4

Answer

$a.\quad x^{2}-81$ $b.\quad 36-m^{4}$ $c.\quad 9c^{2}-16$

Work Step by Step

a. $(x+9)(x-9)$ ...identify which terms correspond to $a $ and $b $ in the rule for the product of a sum and difference.$(a+b)(a-b)=a^{2}-b^{2}$) $a=x,\ b=9$ ...substitute for $a $ and $b $ in the rule $(x+9$)$(x-9)=x^{2}-9^{2}$ ...simplify. $=x^{2}-81$ b. $(6+m^{2})(6-m^{2})$ ...identify which terms correspond to $a $ and $b $ in the rule for the product of a sum and difference.$(a+b)(a-b)=(a^{2}-b^{2}$) $a=6,\ b=m^{2}$ ...substitute for $a $ and $b $ in the rule $(6+m^{2})(6-m^{2})=6^{2}-(m^{2})^{2}$ ...simplify. $=36-m^{4}$ c. $(3c-4)(3c+4)$ ...identify which terms correspond to $a $ and $b $ in the rule for the product of a sum and difference.($(a+b)(a-b)=a^{2}-b^{2}$) $a=3c,\ b=4$ ...substitute for $a $and $b $in the rule $(3c-4)(3c+4)=(3c)^{2}-4^{2}$ ...simplify. $=9c^{2}-16$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.