## Algebra 1: Common Core (15th Edition)

The answer to the question is y $\lt$ $\frac{9+x}{-3}$.
To solve this inequality for y, you add x on both the sides resulting in -3y $\gt$ 9+x. Next, you divide -3 from both the sides resulting in an isolated y. BUT you have to flip the sign of the inequality to $\lt$ because you are dividing from a negative number. The answer is y $\lt$ $\frac{9+x}{-3}$