Answer
$9m^{2}n^{3}(m^{2}n^{2}-3)$
Work Step by Step
List the prime factors of each term. Identify the factors common to all terms.
$9m^{4}n^{5}=(3\cdot 3)\cdot(m\cdot m)\cdot m\cdot m\cdot(n\cdot n\cdot n)\cdot n\cdot n$
$-27m^{2}n^{3}=-1\cdot(3\cdot 3)\cdot 3\cdot(m\cdot m)\cdot(n\cdot n\cdot n)$
GCF=$9m^{2}n^{3}$
$9m^{4}n^{5}-27m^{2}n^{3}\qquad...$factor out the GCF
$=9m^{2}n^{3}(m^{2}n^{2})-9m^{2}n^{3}(3)\qquad
...$
apply the Distributive Property.
$=9m^{2}n^{3}(m^{2}n^{2}-3)$
