## Algebra 1: Common Core (15th Edition)

You have y=100 $\times$ $1.22^{x}$.The population is growing and you have to find the numbers of frogs in 5 years: y=100 $\times$ $1.22^{x}$ y=100 $\times$ $1.22^{5}$ y=270.27 -since you cant have half a frog, the population would be about 270 frogs- y$\approx$270 There will be about 270 frogs in 5 years.