Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-7 Exponential Growth and Decay - Practice and Problem-Solving Exercises - Page 464: 14

Answer

about 270

Work Step by Step

You have y=100 $\times$ $1.22^{x}$.The population is growing and you have to find the numbers of frogs in 5 years: y=100 $\times$ $1.22^{x}$ y=100 $\times$ $1.22^{5}$ y=270.27 -since you cant have half a frog, the population would be about 270 frogs- y$\approx$270 There will be about 270 frogs in 5 years.
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