## Algebra 1: Common Core (15th Edition)

$a.\quad 3$ $b.\quad 2$ $c.\quad 4$ $d.\quad 6$
$a.$ Recognize that $27=3^{3}$ $\sqrt[3]{27}=\sqrt[3]{3^{3}}=3$ $b.$ Recognize that $32=2^{5}$ $\sqrt[5]{35}=\sqrt[5]{2^{5}}=2$ $c.$ Recognize that $64=4^{3}$ $\sqrt[3]{64}=\sqrt[3]{4^{3}}=4$ $d.$ Recognize that $36=6^{2}$ $\sqrt[2]{36}=\sqrt[2]{6^{2}}=6$