Answer
$n^{15}$
Work Step by Step
We are given
$(7^0n^{-3})^2(n^7)^3$
$=(7^0)^2(n^{-3})^2(n^7)^3$
$=1.n^{-6}.n^{21}$
$=n^{15}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 445: 102
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