Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-4 Division Properties of Exponents - Practice and Problem-Solving Exercises - Page 445: 102



Work Step by Step

We are given $(7^0n^{-3})^2(n^7)^3$ $=(7^0)^2(n^{-3})^2(n^7)^3$ $=1.n^{-6}.n^{21}$ $=n^{15}$
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