## Algebra 1: Common Core (15th Edition)

The answer is $z^{\frac{1}{2}}$
To solve $(z^{8})^{0}$ $z^{\frac{1}{2}}$. --> $(z^{8})^{0}$ equals 1 as the exponent is 0 and any number to exponent 0 is 1. 1($z^{\frac{1}{2}}$) = $z^{\frac{1}{2}}$