## Algebra 1: Common Core (15th Edition)

a) $(x^{-2})^2(3xy^5)^4$ $=x^{-4}3^4x^4(y^5)^4$ $=81y^{20}$ b) $(3c^{\frac{5}{2}})^4(c^2)^3$ $=3^4(c^{\frac{5}{2}})^4c^6$ $=81c^{16}$ c) $(6ab)^3(5a^{-3})^2$ $=6^3a^3b^35^2(a^{-3})^2$ $=5400a^{-3}b^3$ $=\frac{5400b^3}{a^3}$