## Algebra 1: Common Core (15th Edition)

a. $x^{-22}$ = $\frac{1}{x^{22}}$ b. $w^{3}$ c. $s^{4}$
To solve a. $x^{2}$($x^{6)^{-4}}$ = $x^{2}$($x^{(6)\times-4}$) = $x^{2}$($x^{-24}$) = $x^{2-24}$ = $x^{-22}$ b. $w^{-2}$($w^{\frac{5}{3})^{3}}$ = $w^{-2}$($w^{(\frac{5}{3})\times3}$) = $w^{-2}$($w^{5}$) = $w^{-2+5}$ = $w^{3}$ c. ($s^{\frac{3}{2}}$)($s^{-5)^{-\frac{1}{2}}}$ = $s^{\frac{3}{2}}$($s^{(-\frac{1}{2})\times-5}$) = $s^{\frac{3}{2}}$($s^{\frac{5}{2}}$) = $s^{\frac{3}{2}+\frac{5}{2}}$ = $s^{\frac{8}{2}}$ = $s^{4}$