#### Answer

$8t^{-8}$= $8/t^8$

#### Work Step by Step

When we multiply two numbers with different exponents but the same base, we raise the base to the power of the two exponents added together. Thus, we know that t should be raised to the power of (-3)+(-5), which equals -8. We also multiply the coefficients, 4 and 2, to get the new coefficient, 8. Thus, our answer is: $8t^{-8}$. Because we have a negative exponent, this can be rewritten as: $8/t^8$.