## Algebra 1: Common Core (15th Edition)

The width of the rectangle is $5.5$ cm, and the length is $16.5$ cm.
Let's set up an equation to find the length of the rectangle using the information we are given: $l = 3w$, where $l$ is the length and $w$ is the width. We can also set up an equation for the perimeter: $2l + 2w = 44$ We see that in the first equation, we already have $y$ expressed in terms of $x$, so we substitute this expression for $y$ in the second equation to find $x$: $2(3w) + 2w = 44$ Multiply first: $6w + 2w = 44$ Combine like terms: $8w = 44$ Divide each side by $8$ to solve for $w$: $w = 5.5$ cm Now, plug in the value for $w$ into the first equation to find $l$: $l = 3(5.5)$ Multiply to solve for $l$: $l = 16.5$ cm