Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - Chapter Review - Page 410: 21


One solution (-11,-7)

Work Step by Step

You have the equations 5x+4y=-83 and 3x-3y=-12. Multiply the first one by 3 and the second by 3 to be able to eliminate them: 3(5x+4y=-83)=15x+12y=-249 -5(3x-3y=-12)=-15x+15y=60 Combine the equations to eliminate them: 15x+12y=-249 -15x+15y=60 27y=-189 -divide both sides by 27- y=-7 Plug in y=-7 into one of the equations: 3x-3(-7)=-12 3x+21=-12 3x=-33 x=-11 There is one solution (-11,-7)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.