Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-4 Applications of Linear Systems - Practice and Problem-Solving Exercises - Page 392: 34

Answer

$x = 4$ $y = 2.5$

Work Step by Step

$5x + 8y = 40$ $3x - 10y = -13$ To use elimination, we need to make one of the variables the same in each equation: $15 + 24y = 120$ $-15x + 50y = 65$ Add the two equations together: $74y = 185$ Divide each side by $74$ to solve for $y$: $y = 2.5$ Now that we have the value for $y$, we can plug it into one of the equations to solve for $x$: $5x + 8(2.5) = 40$ Multiply first: $5x + 20 = 40$ Subtract $20$ from each side of the equation: $5x = 20$ Divide each side of the equation by $5$: $x = 4$
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