Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-2 Solving Systems Using Substitution - Practice and Problem-Solving Exercises - Page 377: 41


Therefore, the system has no solutions.

Work Step by Step

If we solve the first equation for y, $ y+x=x\qquad$ ... add $-x$ $y=0$ Substituting $0$ for $y$ in the second equation, the LHS is undefined, because there is a zero in the denominator. The RHS is defined, the number 4. There is no x that would make this equation true. Therefore, the system has no solutions.
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