## Algebra 1: Common Core (15th Edition)

$6y=-5x+24$ $y=(-5x+24)/6$ as per equation 1. If we substitute in equation 2, $2.5x+3y=12$ $2.5x+3((-5x+24)/6)=12$ $2.5x+(-5x+24)/2=12$ $2.5x-2.5x+12=12$ $12=12$ As LHS = RHS , we can conclude that there are infinitely many solutions, since both the equations are equal.