Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-2 Solving Systems Using Substitution - Practice and Problem-Solving Exercises - Page 376: 27


Infinite solutions.

Work Step by Step

$6y=-5x+24$ $y=(-5x+24)/6$ as per equation 1. If we substitute in equation 2, $2.5x+3y=12$ $2.5x+3((-5x+24)/6)=12$ $2.5x+(-5x+24)/2=12$ $2.5x-2.5x+12=12$ $12=12$ As LHS = RHS , we can conclude that there are infinitely many solutions, since both the equations are equal.
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