Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-2 Solving Systems Using Substitution - Lesson Check - Page 375: 8


Second equation, variable $y.$

Work Step by Step

To avoid fractions in the first step (solving one equation for one of the variables) we seek a variable with coefficients 1 or -1. In this case, the variable y in the second equation would be our choice, as its coefficient is $-1.$ $ 6x-y=1\qquad$ ... add $y-1$ $6x-1=y$ And, in the next step, we would substitute $y$ with $6x-1$ and solve for x.
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