Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-1 Solving Systems by Graphing - Lesson Check - Page 367: 3



Work Step by Step

$y=−3x−3$ $y=2x+2$ Multiply the top equation by $−1$ so that the y values cancel, then you'll have $0=5x+5$ so subtract $ 5$ from both sides to have $−5=5x$ Then on both sides, divide by $5$ to get $x=−1$ Plug in $−1$ for the x value of either equation $y=−3(−1)−3$ to find that $y=0$
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