Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 5 - Linear Functions - Chapter Review - Page 355: 31

Answer

$y = -\frac{1}{8}x + \frac{21}{2}$

Work Step by Step

For perpendicular lines, the product of the slopes of the two lines is $-1$. The equation of the line that we are given is in slope-intercept form, which is given by the formula: $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept. The slope of the line given $y = 8x - 1$ is $8$. The product of the slopes of the two lines must equal $-1$, so let us set up the equation to find the slope $m$ of the unknown line: $8(m) = -1$ Divide each side by $8$ to solve for $m$: $m = \frac{-1}{8}$ Now that we have the slope of the unknown line, we can plug this and the point that we are given $(4, 10)$ into point-slope form, which is given by the formula: $y - y_1 = m(x - x_1)$, where $m$ is the slope and $(x_1, y_1)$ is a point on that graph. Let us plug in the values: $y - 10 = -\frac{1}{8}(x - 4)$ Let's convert this equation into point-intercept form: Use the distributive property: $y - 10 = -\frac{1}{8}x - (\frac{1}{8})(-4)$ Multiply to simplify: $y - 10 = -\frac{1}{8}x + \frac{4}{8}$ Simplify the fraction by dividing the numerator and the denominator by their greatest common factor, which is $4$: $y - 10 = -\frac{1}{8}x + \frac{1}{2}$ To isolate $y$, add $10$ to each side of the equation: $y = -\frac{1}{8}x + \frac{1}{2} + 10$ We need to find an equivalent fraction for $10$ so that the denominator is $2$: $y = -\frac{1}{8}x + \frac{1}{2} + \frac{20}{2}$ Add the fractions to simplify: $y = -\frac{1}{8}x + \frac{21}{2}$ This is the equation of the line that we are looking for in slope-intercept form.
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