Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 5 - Linear Functions - 5-6 Parallel and Perpendicular Lines - Practice and Problem-Solving Exercises - Page 335: 47

Answer

$y = -\frac{40}{7}x + \frac{660}{7}$

Work Step by Step

We are given the points $(13, 20)$ and $(6, 60)$. Let's use the formula to find the slope $m$ given two points: $m = \frac{y_2 - y_1}{x_2 - x_1}$ Let's plug in the values into this formula: $m = \frac{60 - 20}{6 - 13}$ Subtract the numerator and denominator to simplify: $m = \frac{40}{-7}$ Now that we have the slope, we can use one of the points and plug these values into the point-slope equation, which is given by the formula: $y - y_1 = m(x - x_1)$ Let's plug in the points and slope into the formula: $y - 20 = -\frac{40}{7}(x - 13)$ This equation is now in point-slope form. To change this equation into point-intercept form, we need to isolate $y$. Use distribution to simplify: $y - 20 = -\frac{40}{7}x - \frac{40}{7}(-13)$ Simplify by multiplying: $y - 20 = -\frac{40}{7}x + \frac{520}{7}$ To isolate $y$, we add $20$ to each side of the equation: $y = -\frac{40}{7}x + \frac{520}{7} + 20$ Change $20$ into an equivalent fraction that has $7$ as its denominator so that both fractions have the same denominator: $y = -\frac{40}{7}x + \frac{520}{7} + \frac{140}{7}$ Add the fractions to simplify: $y = -\frac{40}{7}x + \frac{660}{7}$ Now, we have the equation of the line in slope-intercept form.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.