Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 5 - Linear Functions - 5-5 Standard Form - Practice and Problem-Solving Exercises - Page 328: 71

Answer

$y - 2 = x - 1$ $y = x + 1$

Work Step by Step

We are given the two points $(-2, -1)$ and $(1, 2)$. Let's use the formula to find the slope $m$ given two points: $m = \frac{y_2 - y_1}{x_2 - x_1}$ Let's plug in the values into this formula: $m = \frac{2 - (-1)}{1 - (-2))}$ Subtract the numerator and denominator to simplify: $m = \frac{3}{3}$ Simplify the fraction by dividing both the numerator and denominator by their greatest common factor, which is $3$: $m = 1$ Now that we have the slope, we can use one of the points and plug these values into the point-slope equation, which is given by the formula: $y - y_1 = m(x - x_1)$ Let's plug in the points and slope into the formula: $y - 2 = x - 1$ To change this equation into slope-intercept form, we need to isolate $y$. To isolate $y$, we add $2$ to each side of the equation: $y = x - 1 + 2$ Add the constants to simplify: $y = x + 1$ Now, we have the equation of the line in slope-intercept form.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.