## Algebra 1: Common Core (15th Edition)

$3x+4y=12$
You are given the x and y intercept $(4,0)$ and $(0,3)$ Find the slope: $m=\dfrac{3-0}{0-4}$ $m=-\dfrac{-3}{4}$ Plug into slope formula: $y=mx+b$ $0=-\dfrac{3}{4}(4)+b$ $0=-3+b$ $3=b$ Put into the standard form: $y=-\dfrac{3}{4}x+3$ $4y=-3x+12$ $3x+4y=12$