## Algebra 1: Common Core (15th Edition)

You are given the equation: $\frac{q}{3}$-3=6 and you have to solve for q: $\frac{q}{3}$-3=6 -add 3 to both sides- $\frac{q}{3}$=9 -multiply both sides by 3- q=27 Check your work: $\frac{27}{3}$-3=6 9-3=6 The equation is equal so q=27.