## Algebra 1: Common Core (15th Edition)

We are given: $3y+6=-2x$ Subtract 6 from each side: $3y=-2x-6$ Then divide each side by 3: $y=-\frac{2}{3}x-2$ The y-intercept is $-2$, so plot a point at $(0,-2)$. The slope is $\frac{-2}{3}$. Some values of x and y $x=1: y=\frac{-8}{3} \rightarrow (1,\frac{-8}{3})$ $x=2: y=\frac{-10}{3} \rightarrow (2,\frac{-10}{3})$ $x=3: y=-4\rightarrow (3,-4)$