## Algebra 1: Common Core (15th Edition)

You have to put it into slope-intercept form. Use two points (-2,4)(3,-1) and use the slope formula (m=$\frac{y2-y1}{x2-x1}$): m=$\frac{-1-4}{3-(-2)}$=$\frac{-5}{5}$. The slope is -1. Plug the slope and the two points into the slope-intercept form: y=mx+b 4=-1(-2)+b b=2 Now, put the values into the equation: y=-x+2.