Algebra 1: Common Core (15th Edition)

a) $A(n)=A(n-1)+10$ with $A(1)=76$ b) $A(n)=A(n-1)+3$ with $A(1)=1$
a) We have $A(n)=76+(n-1)(10)$ 76 is the first term 10 is the common difference. The recursive formula is $A(n)=A(n-1)+10$ with $A(1)=76$ b) We have $A(n)=1+(n-1)(3)$ 1 is the first term 3 is the common difference. The recursive formula is $A(n)=A(n-1)+3$ with $A(1)=1$