Answer
a) $A(n)=A(n-1)+10$ with $A(1)=76$
b) $A(n)=A(n-1)+3$ with $A(1)=1$
Work Step by Step
a) We have $A(n)=76+(n-1)(10)$
76 is the first term
10 is the common difference.
The recursive formula is $A(n)=A(n-1)+10$ with $A(1)=76$
b) We have $A(n)=1+(n-1)(3)$
1 is the first term
3 is the common difference.
The recursive formula is $A(n)=A(n-1)+3$ with $A(1)=1$
