## Algebra 1: Common Core (15th Edition)

To solve this, we can say that Andrew needs x dollars, so A=x. Since Scott needs two more dollars than Andrew, then S=x+2. Since Nick needs half as much as Andrew, then N=$\frac{1}{2}$x. Adding A+S+N=17 as they need 17 dollars so we can solve for x. x+(x+2)+$\frac{1}{2}$x=17 2x+$\frac{1}{2}$x=17-2 $\frac{5}{2}$x=15 5x=30 x=6 So;1 $\frac{1}{2}$x=$\frac{1}{2}$(6)=3 Therefore Nick needs \$3.