Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 4 - An Introduction to Functions - 4-6 Formalizing Relations and Functions - Practice and Problem-Solving Exercises: 20

Answer

Therefore we get the range to be {0, 0.04 , 1.44 , 16}

Work Step by Step

h(x) = x2 The domain is {-1.2,0,0.2,1.2,4}. The domain gives the x value so we substitute the x into the equation h(x) = x2 x=-1.2 $h(-1.2) = (−1.2)^2$ h(-1.2) = 1.44 x=0 $h(0) = (0)^2$ h(0) = 0 x=0.2 $h(0.2) = (0.2)^2$ h(0.2) = 0.04 x=1.2 $h(1.2) = (1.2)^2$ h(1.2) = 1.44 x=4 $h(4) = (4)^2$ h(4) = 16 Therefore we get the range to be {0, 0.04 , 1.44 , 16}
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