Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 4 - An Introduction to Functions - 4-5 Writing a Function Rule - Practice and Problem-Solving Exercises: 20

Answer

V= 138.16 $in^3$

Work Step by Step

$V= πr^2 (4r+3)$ The volume of the cylinder when it has a radius of 2 in. is 138.16 in3 Work Step by Step The formula for the volume of a cylinder is $V= πr^2 h$ and in this scenario, the height is 3 plus 4 times the radius this h= 4r+3, therefore substituting 4r+3 for h we get $V= πr^2$ (4r+3) For the question, What is the volume of the cylinder when it has a radius of 2 in.? We substitute 2 for r. r=2 $V= πr^2$ (4r+3) $V= (3.14) (2)^2$ (4(2)+3) V= 138.16 $in^3$
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