## Algebra 1: Common Core (15th Edition)

$c = -6$ or $c = \frac{16}{3}$
Add $4$ to each side of the equation: $|3c + 1| = 17$ To get rid of the absolute value sign, rewrite the equation as two separate equations: $3c + 1 = -17$ or $3c + 1 = 17$ Subtract $1$ from both sides of the equation: $3c = -18$ or $3c = 16$ Divide both sides of the equation by $3$: $c = -6$ or $c = \frac{16}{3}$