Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 3 - Solving Inequalities - 3-5 Working With Sets - Practice and Problem-Solving Exercises - Page 198: 47


$T'=\{ ...,-2,-1,0\}$

Work Step by Step

We have $U=\{ ...,-1,0,1,2,..12 \}$ and $T=\{ 1,2,3,...12 \}$ The complement of set T is the set of all elements in the universal set that are not in the set. So $T'=\{ ...,-2,-1,0\}$
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