## Algebra 1: Common Core (15th Edition)

$a) 73$ boxes $b)4$ trips
a) $50x+210+95\leq4000$ 210+95=305: $50x+305\leq4000$ 4000-305= 3695: $50x\leq3695$ Divide both sides by 50: $\frac{50x}{50}=\frac{3695}{50}$ Simplify: $x\leq73.9$ b) Divide 275 by 73: $\frac{275}{75}\approx3.8$ This means that he can make 3 trips with a full load, and the 4th trip has to be less than full. 4 trips