Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 3 - Solving Inequalities - 3-4 Solving Multi-Step Inequalities - Got It? - Page 188: 4

Answer

a) $b>3$ b) possible first step: add $1$ to both sides of the inequality

Work Step by Step

a) Using the properties of equality, the solution to the given inequality is $$\begin{aligned} 3b+12&>27-2b \\ 3b+2b&>27-12 \\ 5b&>15 \\ b&>\frac{15}{5} \\ b&>3 .\end{aligned} $$ Checking: Substituting any value of $b$ greater than $3$ (such as $b=4$) in the original equality results in $$\begin{aligned} 3(4)+12&\overset{?}>27-2(4) \\ 12+12&\overset{?}>27-8 \\ 24&\overset{\checkmark}>19\text{ (TRUE)} .\end{aligned} $$Since the substitution above ended with a TRUE statement, then the solution is indeed $b>3$. b) In Problem $4$, the first step can also be to add $1$ to both sides of the inequality. It can also be to subtract $6n$ to both sides. Or it can also be to subtract $8$ to both sides. In all of these possibilities, the idea is to isolate the variable on one side.
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