## Algebra 1: Common Core (15th Edition)

distance travelled=speed$\times$time $time=\frac{distance}{speed}\leq25$ $0.08$ miles/minute
distance travelled=speed$\times$time to be at the park in at most 25 min, we need to have $time=\frac{distance}{speed}\leq25$ to solve the problem you need to have $\frac{distance}{25}\leq speed$ because the distance is equal to 2 miles, you can conclude that $\frac{2}{25}\leq speed$ Simplify: $0.08\leq speed$ this means that he needs to run at a speed greater than $0.08$ miles/minute