Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 2 - Solving Equations - Concept Byte - Page 122: 4

Answer

See answer below

Work Step by Step

We need to choose conversion factors that the original units (yards and seconds) can divide out, leaving us with the units we need. Here we have the speed of light represented as $3.0 \times 10^{10}cm/s$ Using appropriate conversion factors: $\frac{3.0 \times 10^{10} cm}{1 s}.\frac{1 mi}{160934 cm}.\frac{3600s}{1h}$ $\frac{1 mi}{160934 cm} \rightarrow $ This conversion factor cancels cm and leaves miles. $\frac{3600s}{1h} \rightarrow $ This conversion factor cancels seconds and leaves hours.
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