## Algebra 1: Common Core (15th Edition)

4a. $3(4b-2)=-6+12b$ Expand: $12b-6=-6+12b$ Add 6 to both sides: $12b-6+6=-6+12b+6$ Simplify: $12b=12b$ Subtract 12b from both sides: $12b-12b=12b-12b$ Simplify: $0=0$ Both sides are equal: True for all b 4b. $2x+7=-1(3-2x)$ Expand: $2x+7=-3+2x$ Subtract 7 from both sides: $2x+7-7=-3+2x-7$ Simplify: $2x=2x-10$ Subtract 2x form both sides: $2x-2x=2x-10-2x$ Simplify: $0=-10$ The sides are not equal: No solution