## Algebra 1: Common Core (15th Edition)

$14,15,16$
You have to find 3 consecutive numbers that equal $45$. Let x be the first number. The next number is greater than x so it will be $x+1$.The next consecutive number is 2 greater than x so it will be $x+2$.Use this to make an equation: $x+x+1+x+2=45$ (simplify) $3x+3=45$ (subtract both sides by 2) $3x=42$ (divide both sides 3 to get the first consecutive number) $x=14$ The first consecutive number is 14. The second number is 14+1=15. The third number is 14+2=16.