Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 2 - Solving Equations - 2-3 Solving Multi-Step Equations - Practice and Problem-Solving Exercises - Page 100: 66



Work Step by Step

You have to find 3 consecutive numbers that equal $45$. Let x be the first number. The next number is greater than x so it will be $x+1$.The next consecutive number is 2 greater than x so it will be $x+2$.Use this to make an equation: $x+x+1+x+2=45$ (simplify) $3x+3=45$ (subtract both sides by 2) $3x=42$ (divide both sides 3 to get the first consecutive number) $x=14$ The first consecutive number is 14. The second number is 14+1=15. The third number is 14+2=16.
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