## Algebra 1: Common Core (15th Edition)

3a. $18=3(2x-6)$ Switch sides: $3(2x-6)=18$ Multiply one side by 3: $6x-18=18$ Add 18 to both sides: $6x-18+18=18+18$ Simplify:$6x=36$ Divide both sides by 6:$\frac{6x}{6}=\frac{36}{6}$ Simplify:$x=6$ 3b. You can use the division property to solve this equation Switch sides: $3(2x-6)=18$ Divide both sides by 3: $\frac{3(2x-6)}{3}=\frac{18}{3}$ Simplify: $2x-6=6$ Add 6 to both sides: $2x-6+6=6+6$ Simplify:$2x=12$ Divide both sides by 2:$\frac{2x}{2}=\frac{12}{2}$ Simplify:$x=6$