## Algebra 1: Common Core (15th Edition)

The 3 is being divided by 5. If we were to add 3 first, we would be acting like the three was not being divided by 5, which would mean the equation would have to be $\frac{d}{5}-3.$ However, because the equation is actually $\frac{d-3}{5}$, we have to multiply by 5 first so that the 3 is no longer being divided by 5.