## Algebra 1: Common Core (15th Edition)

$V=\pi r^{2}h$- formula for the volume of a cylinder $0.5$ This is the accurate possible error to the nearest foot The measured volume $V=(3.14)(2.5)^2(2)$ $v=39.25$ The minimum volume the diameter is 5ft so the possible minimum error is 4.5ft (5ft-0.5ft). The radius is half of the diameter: $4.5\div2=2.25$ $V=(3.14)(2.25)^2(1.5)$ $V=23.84$ The maximum volume The maximum volume the diameter is 5ft so the possible minimum error is 5.5ft (5ft+0.5ft). The radius is half of the diameter: $5.5\div2=2.75$ $V=3.14(2.75)^2(2.5)$ $59.37$ Difference in volume $|23.84-39.25|$ $15.41$ Difference in volume $|59.37-39.25|$ $20.12$ Greatest possible percent error=greatest difference in volume/measured volume $\frac{20.12}{39.25}\approx0.5126$ or $51.26$%