## Algebra 1: Common Core (15th Edition)

z=7$\frac{1}{3}$
In order to solve this algebraic expression, we must isolate the variable. A variable is the letter in the problem (for instance, in the equation x+2=10, x is the variable). Because addition and subtraction are inverse operations (they cancel each other out), we know we must add when a number is being subtracted from the variable and subtract when a number is being added to the variable. In the equation z-4$\frac{2}{3}$=2$\frac{2}{3}$, we must get rid of the 4$\frac{2}{3}$, which is on the same side as z, in order to solve. Thus, we add 4$\frac{2}{3}$ on both sides of the equation to find that z=7$\frac{1}{3}$. We plug 7$\frac{1}{3}$ in for z and confirm that our answer is, indeed, correct.