## Algebra 1: Common Core (15th Edition)

Use P(7)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$. There are 6 possible outcomes:1,2,3,4,5 and 6. There are 0 favorable outcomes because you do not have the value 7. Plug in the number of outcomes: P(7)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$. P(7)=$\frac{0}{6}$ P(7)=0