Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - Chapter Review - Page 789: 32

Answer

35

Work Step by Step

Use the formula of combination: $_{n}$C$_{r}$=$\frac{n!}{r!(n-r)!}$. Plug in 7 for N and 3 for R: $_{n}$C$_{r}$=$\frac{n!}{r!(n-r)!}$ $_{7}$C$_{3}$=$\frac{7!}{3!(7-3)!}$ -simplify like terms- $_{7}$C$_{3}$=$\frac{7!}{3! (4!)}$ -write using factorial- $_{7}$C$_{3}$=$\frac{7*6*5*4*3*2*1}{(3*2*1)(4*3*2*1)}$ -simplify- $_{7}$C$_{3}$=35
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