Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - Chapter Review - Page 789: 29

Answer

126

Work Step by Step

Use the formula of combination: $_{n}$P$_{r}$=$\frac{n!}{r!(n-r)!}$. Plug in 9 for N and 4 for R: $_{n}$P$_{r}$=$\frac{n!}{r!(n-r)!}$ $_{9}$P$_{4}$=$\frac{9!}{4!(9-4)!}$ -simplify like terms- $_{9}$P$_{4}$=$\frac{9!}{4! (5!)}$ -write using factorial- $_{9}$P$_{4}$=$\frac{9*8*7*6*5*4*3*2*1}{(4*3*2*1)(5*4*3*2*1)}$ -simplify- $_{9}$P$_{4}$=126
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