Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - 12-8 Probability of Compound Events - Practice and Problem-Solving Exercises - Page 782: 44

Answer

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Work Step by Step

a) P (red 1) $=\frac{1}{6}$ P (yellow 1) $=\frac{1}{6}$ P (red 1 and yellow 1) = $\frac{1}{6}.\frac{1}{6}=\frac{1}{36}$ b) P (red 2) $=\frac{1}{6}$ P (yellow 2) $=\frac{1}{6}$ P (red 1 and yellow 1) = $\frac{1}{6}.\frac{1}{6}=\frac{1}{36}$ c) Rolling any matching pair of numbers means: P (red 1 and yellow 1) $=\frac{1}{6}$ P (red 2 and yellow 2) $=\frac{1}{6}$ P (red 3 and yellow 3) $=\frac{1}{6}$ P (red 4 and yellow 4) $=\frac{1}{6}$ P (red 5 and yellow 5) $=\frac{1}{6}$ P (red 6 and yellow 6) $=\frac{1}{6}$ P (red 1 and yellow 1) = $\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=\frac{6}{36}=\frac{1}{6}$
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