Answer
Minimum=3.2.1st quartile=4.5.Median=5.3rd quartile=6 . Maximum=12
Work Step by Step
You have the values: 3.3,3.9,4.5,4.9,5,5.2,6,6.3,12.
-->Minimum is the smallest value in the data set which is 3.2.
-->Arrange the data from least to greatest(3.3,3.9,4.5,4.9,5,5.2,6,6.3,12) to find the middle number.The median is 5.
-->The maximum is the largest value in the set which is 12.
-->The first quartile is the middle value between the minimum and median:(3.2,3.9,4.5,4.9,5)The middle value is 4.5
-->The third quartile is the middle value between the median and the maximum(5,5.2,6,6.3,12). The middle value is 6.
Minimum=3.2.1st quartile=4.5.Median=5.3rd quartile=6 .Maximum=12
